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Table 5 Distribution of fungal isolates with respect to currency type, denomination and source

From: Public health implications of contamination of Franc CFA (XAF) circulating in Buea (Cameroon) with drug resistant pathogens

Currency denomination

Fungi isolated N (%)

Absidia sp

Acremonium sp

Aspergillus sp

Blastomyces sp

Epidermophyton sp

Fusrium sp

Scopulariopsis sp

Sporothrix sp

Microsporum sp

Candida albicans

Candida sp

Penicillium sp

Rhyzopus sp

Saccharomyces cerevisiae

Trichophyton sp

Note

500

0 (0.0)

0 (0.0)

5 (2.3)

0 (0.0)

0 (0.0)

0 (0.0)

0(0.0)

0 (0.0)

0 (0.0)

0 (0.0)

2 (0.9)

4 (1.8)

3 1.4)

1(0.5)

2 (0.9)

1000

0 (0.0)

0 (0.0)

11 (5.1)

2 (0.9)

2 (0.9)

0 (0.0)

0 (0.0)

2(0.9)

2 (0.9)

2 (0.9)

4 (1.8)

11 (5.1)

5 (2.3)

8 (3.7)

6 (2.8)

2000

1 (0.5)

0 (0.0)

10 (4.7)

0 (0.0)

0 (0.0)

0 (0.0)

1 (0.5)

0 (0.0)

0 (0.0)

2 (0.9)

6 (2.8)

10 (4.6)

5 (2.3)

4 (1.8)

3 (1.4)

5000

0 (0.0)

0 (0.0)

3 (1.4)

0 (0.0)

0 (0.0)

0 (0.0)

0 (0.0)

0 (0.0)

0 (0.0)

0 (0.0)

1 (0.5)

0 (0.0)

1 (0.5)

0 (0.0)

1 (0.5)

10000

0 (0.0)

1 (0.5)

1 (0.5)

0 (0.0)

0 (0.0)

0 (0.0)

0 (0.0)

0 (0.0)

1 (0.5)

1 (0.5)

1 (0.5)

0 (0.0)

3 (1.4)

3 (1.4)

0 (0.0)

Coin

50

0 (0.0)

0 (0.0)

2 (0.9)

0 (0.0)

1 (0.5)

0 (0.0)

0 (0.0)

0 (0.0)

0 (0.0)

0 (0.0)

1 (0.9)

3 (1.4)

0 (0.0)

1 (0.5)

0 (0.0)

100

0 (0.0)

0 (0.0)

2 (0.9)

0 (0.0)

1 (0.5)

1 (0.5)

0 (0.0)

0 (0.0)

0 (0.0)

0 (0.0)

4 (1.8)

5 (2.3)

2 (0.9)

6 (2.8)

5 (2.3)

500

0 (0.0)

0 (0.0)

3 (1.4)

0 (0.0)

1 (0.5)

0 (0.0)

0 (0.0)

0 (0.0)

0 (0.0)

2 (0.9)

0 (0.0)

1 (0.5)

0 (0.0)

0 (0.0)

1 (0.0)

Total

1 (0.5)

1 (0.5)

37 (17.3)

2 (0.9)

5 (2.3)

1 (0.5)

1 (0.5)

2 (0.9)

3 (1.4)

7 (3.2)

19 (8.9)

34 (15.9)

19 (8.9)

23 (10.7)

18 (8.4)

χ 2 -test

χ2 = 3.996 df = 7 P = 0.780

χ2 = 12.525 df = 7 P = 0.085

χ2 = 9.490 df = 7 P = 0.219

χ2 = 7.042 df = 7 P = 0.425

χ2 = 5.969 df = 7 P = 0.543

χ2 = 4.893 df = 7 P = 0.673

χ 2 =3.996 df = 7 P = 0.780

χ 2 =7.042 df = 7 P = 0.425

χ2 = 7.576 df = 7 P = 0.371

χ2 = 12.617 df = 7 P = 0.082

χ2 = 3.367 df = 7 P = 0.849

χ2 = 10.061 df = 7 P = 0.185

χ2 = 6.875 df = 7 P = 0.442

χ2 = 9.170 df = 7 P = 0.241

χ2 = 6.132 df = 7 P = 0.524

Source of currency

               

Butchers

1 (0.5)

0 (0.0)

8 (3.7)

0 (0.0)

2 (0.9)

0 (0.0)

0 (0.0)

2 (0.9)

2 (0.9)

0 (0.0)

5 (2.3)

2 (0.9)

5 (2.3)

4 (1.8)

6 (2.8)

Food vendors

0 (0.0)

0 (0.0)

12 (5.6)

2 (0.9)

1 (0.5)

1 (0.5)

1 (0.5)

0 (0.0)

1 (0.5)

3 (1.4)

4 (1.8)

12 (5.6)

5 (2.3)

8 (3.7)

8 (3.7)

Store attendants

0 (0.0)

0 (0.0)

1 (0.5)

0 (0.0)

0 (0.0)

0 (0.0)

0 (0.0)

0 (0.0)

0 (0.0)

0 (0.0)

1 (0.5)

4 (1.8)

4 (1.8)

1 (0.5)

1 (0.5)

Students

0 (0.0)

1 (0.5)

7 (3.2)

0 (0.0)

0 (0.0)

0 (0.0)

0 (0.0)

0 (0.0)

0 (0.0)

0 (0.0)

1 (0.5)

10 (4.7)

0 (0.0)

2 (0.9)

0 (0.0)

Hospital/Clinic

0 (0.0)

0 (0.0)

5 (2.3)

0 (0.0)

2 (0.9)

0 (0.0)

0 (0.0)

0 (0.0)

0 (0.0)

3 (1.4)

5 (2.3)

6 (2.8)

5 (2.3)

8 (3.7)

2 (0.9)

Taxi drivers

0 (0.0)

0 (0.0)

4 (1.8)

0 (0.0)

0 (0.0)

0 (0.0)

0 (0.0)

0 (0.0)

0 (0.0)

1 (0.5)

3 (1.4)

0 (0.0)

0 (0.0)

0 (0.0)

1 (0.5)

Butchers

1 (0.5)

0 (0.0)

8 (3.7)

0 (0.0)

2 (0.9)

0 (0.0)

0 (0.0)

2 (0.9)

2 (0.9)

0 (0.0)

5 (2.3)

2 (0.9)

5 (2.3)

4 (1.8)

6 (2.8)

Food vendors

0 (0.0)

0 (0.0)

12 (5.6)

2 (0.9)

1 (0.5)

1 (0.5)

1 (0.5)

0 (0.0)

1 (0.5)

3 (1.4)

4 (1.8)

12 (5.6)

5 (2.3)

8 (3.7)

8 (3.7)

χ 2 -test

χ2 = 5.567 df = 5 P = 0.473

χ2 = 9.450 df = 5 P = 0.150

χ2 = 13.880 df = 5 P = 0.031

χ2 = 6.233 df = 5 P = 0.398

χ2 = 4.197 df = 5 P = 0.650

χ2 = 3.103 df = 5P = 0.796

χ2 = 3.103 df = 5 P = 0.796

χ2 = 11.183 df = 5 P = 0.083

χ2 = 7.181 df = 5 =0.304

χ2 = 4.872 df = 5 P = 0.560.

χ2 = 4.822 df = 5 P = 0.567.

χ2 = 28.674 df = 5 P < 0.001

χ2 = 11.081df = 5 P = 0.086

χ2 = 6.542

df = 5

P = 0.365

χ2 = 12.751

df = 5

P = 0.04

  1. N = Number isolated.